Optimal. Leaf size=92 \[ \frac{(a B+3 A b) \tan ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{a}}\right )}{8 a^{5/2} b^{3/2}}+\frac{x (a B+3 A b)}{8 a^2 b \left (a+b x^2\right )}+\frac{x (A b-a B)}{4 a b \left (a+b x^2\right )^2} \]
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Rubi [A] time = 0.0908262, antiderivative size = 92, normalized size of antiderivative = 1., number of steps used = 3, number of rules used = 3, integrand size = 17, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.176 \[ \frac{(a B+3 A b) \tan ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{a}}\right )}{8 a^{5/2} b^{3/2}}+\frac{x (a B+3 A b)}{8 a^2 b \left (a+b x^2\right )}+\frac{x (A b-a B)}{4 a b \left (a+b x^2\right )^2} \]
Antiderivative was successfully verified.
[In] Int[(A + B*x^2)/(a + b*x^2)^3,x]
[Out]
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Rubi in Sympy [A] time = 12.7736, size = 78, normalized size = 0.85 \[ \frac{x \left (A b - B a\right )}{4 a b \left (a + b x^{2}\right )^{2}} + \frac{x \left (3 A b + B a\right )}{8 a^{2} b \left (a + b x^{2}\right )} + \frac{\left (3 A b + B a\right ) \operatorname{atan}{\left (\frac{\sqrt{b} x}{\sqrt{a}} \right )}}{8 a^{\frac{5}{2}} b^{\frac{3}{2}}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate((B*x**2+A)/(b*x**2+a)**3,x)
[Out]
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Mathematica [A] time = 0.106749, size = 84, normalized size = 0.91 \[ \frac{(a B+3 A b) \tan ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{a}}\right )}{8 a^{5/2} b^{3/2}}+\frac{x \left (a^2 (-B)+a b \left (5 A+B x^2\right )+3 A b^2 x^2\right )}{8 a^2 b \left (a+b x^2\right )^2} \]
Antiderivative was successfully verified.
[In] Integrate[(A + B*x^2)/(a + b*x^2)^3,x]
[Out]
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Maple [A] time = 0.012, size = 90, normalized size = 1. \[{\frac{1}{ \left ( b{x}^{2}+a \right ) ^{2}} \left ({\frac{ \left ( 3\,Ab+Ba \right ){x}^{3}}{8\,{a}^{2}}}+{\frac{ \left ( 5\,Ab-Ba \right ) x}{8\,ab}} \right ) }+{\frac{3\,A}{8\,{a}^{2}}\arctan \left ({bx{\frac{1}{\sqrt{ab}}}} \right ){\frac{1}{\sqrt{ab}}}}+{\frac{B}{8\,ab}\arctan \left ({bx{\frac{1}{\sqrt{ab}}}} \right ){\frac{1}{\sqrt{ab}}}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int((B*x^2+A)/(b*x^2+a)^3,x)
[Out]
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Maxima [F] time = 0., size = 0, normalized size = 0. \[ \text{Exception raised: ValueError} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((B*x^2 + A)/(b*x^2 + a)^3,x, algorithm="maxima")
[Out]
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Fricas [A] time = 0.242552, size = 1, normalized size = 0.01 \[ \left [\frac{{\left ({\left (B a b^{2} + 3 \, A b^{3}\right )} x^{4} + B a^{3} + 3 \, A a^{2} b + 2 \,{\left (B a^{2} b + 3 \, A a b^{2}\right )} x^{2}\right )} \log \left (\frac{2 \, a b x +{\left (b x^{2} - a\right )} \sqrt{-a b}}{b x^{2} + a}\right ) + 2 \,{\left ({\left (B a b + 3 \, A b^{2}\right )} x^{3} -{\left (B a^{2} - 5 \, A a b\right )} x\right )} \sqrt{-a b}}{16 \,{\left (a^{2} b^{3} x^{4} + 2 \, a^{3} b^{2} x^{2} + a^{4} b\right )} \sqrt{-a b}}, \frac{{\left ({\left (B a b^{2} + 3 \, A b^{3}\right )} x^{4} + B a^{3} + 3 \, A a^{2} b + 2 \,{\left (B a^{2} b + 3 \, A a b^{2}\right )} x^{2}\right )} \arctan \left (\frac{\sqrt{a b} x}{a}\right ) +{\left ({\left (B a b + 3 \, A b^{2}\right )} x^{3} -{\left (B a^{2} - 5 \, A a b\right )} x\right )} \sqrt{a b}}{8 \,{\left (a^{2} b^{3} x^{4} + 2 \, a^{3} b^{2} x^{2} + a^{4} b\right )} \sqrt{a b}}\right ] \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((B*x^2 + A)/(b*x^2 + a)^3,x, algorithm="fricas")
[Out]
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Sympy [A] time = 2.82895, size = 150, normalized size = 1.63 \[ - \frac{\sqrt{- \frac{1}{a^{5} b^{3}}} \left (3 A b + B a\right ) \log{\left (- a^{3} b \sqrt{- \frac{1}{a^{5} b^{3}}} + x \right )}}{16} + \frac{\sqrt{- \frac{1}{a^{5} b^{3}}} \left (3 A b + B a\right ) \log{\left (a^{3} b \sqrt{- \frac{1}{a^{5} b^{3}}} + x \right )}}{16} + \frac{x^{3} \left (3 A b^{2} + B a b\right ) + x \left (5 A a b - B a^{2}\right )}{8 a^{4} b + 16 a^{3} b^{2} x^{2} + 8 a^{2} b^{3} x^{4}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((B*x**2+A)/(b*x**2+a)**3,x)
[Out]
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GIAC/XCAS [A] time = 0.22289, size = 105, normalized size = 1.14 \[ \frac{{\left (B a + 3 \, A b\right )} \arctan \left (\frac{b x}{\sqrt{a b}}\right )}{8 \, \sqrt{a b} a^{2} b} + \frac{B a b x^{3} + 3 \, A b^{2} x^{3} - B a^{2} x + 5 \, A a b x}{8 \,{\left (b x^{2} + a\right )}^{2} a^{2} b} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((B*x^2 + A)/(b*x^2 + a)^3,x, algorithm="giac")
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